The distance of an image v from a mirror is given by 1 __
u + 1 __
v = 1 __
of the object from the mirror and f is the focal length of the mirror. u, v and f are all measured in centimetres. Express v in term of u and f. If u = 30 cm and f = 20 cm, fi nd v.
f
Solution 1
__ u + 1
__ v = 1
__ f [Multiply all terms by uvf.]
vf + uf = uv uf = uv − vf uf = v(u − f )
_____ u − f = v
uf v =
u = 30 and f = 20: v = 30 × 20 _______
_____ u − f
uf 30 − 20 = 60 cm EXERCISE 4
1. Solve the following for the letter in the bracket:
(a) y = x + 4 (x) (b) y = 3x (x) (c) y = 3x + 4 (x)
(d) I = PRT ____
(e) w __
p = 2p l ___
100 (T ) d (d)
(f ) v 2 = u 2 + 2as (a) (g) S = 2p r (r + h) (h) (h) (m + n)V = na (n) (i) A = p r 2h (r)