Trans RINA, Vol 161, Part A4, Intl J Maritime Eng, Oct-Dec 2019
4 x
z
42+ EI EI x
+ ( +
+ +
ff q
q t
+ ( 1)− + = t
q
22 z t
q zt zt and qt qt (0, ) 0 , (1, ) 0 ,
==
qt x
2
==
qt x
2
(1, ) 2
(0, ) 2
0 , 0
Besides, a random noise with an amplitude of order O(10-3) is applied to the fluid variable q for the initial conditions (Violette, et al, 2007):
zx and q x O(10 ) , ( ,0)
==
−3 qx
( ,0) t
0 (9b)
It has to be mentioned that θ is the angle between the pipeline and the direction of gravity, and the slope of the seabed or the inclination angle of the pipeline is assumed
to be γ, and =− .
2
3. INTEGRAL TRANSFORM SOLUTION
In this section, the coupling system, i.e. the initial- and boundary-value problem given by Equations (8) and (9) are solved through GITT. This method is a semi-analytical method, which is a classical approach for solving heat and fluid flow problems, and can realize controlled accuracy and efficient computational performance (Cotta, 1993; Cotta, 1994; Cotta, 1997 and Cotta, 1998). The application
©2019: The Royal Institution of Naval Architects
Yk ,,(0) 0 d x
Yk (1) 0 ,
== ==
d (0) 2
2
d (1) 2
2 Yk d x Yk 0 0
whereXand i are the eigenfunction and the eigenvalue of problem Equation (10a); likewise Y and k
eigenfunction and the eigenvalue of problem Equation (10b). The eigenfunctions both satisfy the following orthogonality, 1
k Y x Y x x N= kl k 0 k ( ) ( )dl
where ij and kl kl 0
X x X x x N= ij i 1
0 i ( ) ( )dj (12a) (12b)
=ij 0 ; and for ij =ij 1 . Likewise, for kl = ; for kl
= , = . kl 1 A-325
is the Kronecker delta. For ij = ,
, ,
are the (11b) ( ,0) 0 ,
==
zx
( ,0) t
0 (9a) (8c) (0, ) 0 , (1, ) 0 ,
==
zt x
2
==
zt x
2
(1, ) 2
(0, ) 2
0 , 0 (8b)
of GITT has been further adopted in the area of structural mechanics (Ma, et al, 2006; An & Su, 2011; Matt, 2013a; Matt, 2013b; An & Su, 2014a; and An & Su, 2014b). The implementation of this technique to solve coupled fluid and structure problems has been more frequent over the last few years (Matt, 2009; Gu, et al, 2012; Gu, et al, 2013a; Gu, et al, 2013b; An & Su, 2015; An, et al, 2016; Li, et al, 2016; and Gu, et al, 2016).
The first step in applying GITT is to define the auxiliary eigenvalue problem. For the transverse displacement of a pipeline and the wake variable, the eigenvalue problems are chosen respectively as:
d ( )Xx X x( ), 0 1 4
4
d x = ii 4
i
d ( )Yx Y x( ), 0 1 4
4
d x = kk 4
k
with the boundary conditions being: 2
X ,,(0) 0 d x
i i X (1) 0 ,
== ==
d (0) 2
Xi
d (1) 2
2 Xi d x 0 0 (11a) x x (10a) (10b) () sf
rr L zz gA i
+m mi gL) sin q (
mm mm
miU L T L −
2 PAi 2 2 a EImp + )
pp p
z
2
(m m gL) cosz EI
2 pi +
tt m
+ + mp
e )
22 22
2 2 + ( x 4 p EID − 3 +
eesin L EID
4 =
2miU z x t
2 (8a)
together with the dimensionless boundary conditions expressed as:
Page 1 |
Page 2 |
Page 3 |
Page 4 |
Page 5 |
Page 6 |
Page 7 |
Page 8 |
Page 9 |
Page 10 |
Page 11 |
Page 12 |
Page 13 |
Page 14 |
Page 15 |
Page 16 |
Page 17 |
Page 18 |
Page 19 |
Page 20 |
Page 21 |
Page 22 |
Page 23 |
Page 24 |
Page 25 |
Page 26 |
Page 27 |
Page 28 |
Page 29 |
Page 30 |
Page 31 |
Page 32 |
Page 33 |
Page 34 |
Page 35 |
Page 36 |
Page 37 |
Page 38 |
Page 39 |
Page 40 |
Page 41 |
Page 42 |
Page 43 |
Page 44 |
Page 45 |
Page 46 |
Page 47 |
Page 48 |
Page 49 |
Page 50 |
Page 51 |
Page 52 |
Page 53 |
Page 54 |
Page 55 |
Page 56 |
Page 57 |
Page 58 |
Page 59 |
Page 60 |
Page 61 |
Page 62 |
Page 63 |
Page 64 |
Page 65 |
Page 66 |
Page 67 |
Page 68 |
Page 69 |
Page 70 |
Page 71 |
Page 72 |
Page 73 |
Page 74 |
Page 75 |
Page 76 |
Page 77 |
Page 78 |
Page 79 |
Page 80 |
Page 81 |
Page 82 |
Page 83 |
Page 84 |
Page 85 |
Page 86 |
Page 87 |
Page 88 |
Page 89 |
Page 90 |
Page 91 |
Page 92 |
Page 93 |
Page 94 |
Page 95 |
Page 96 |
Page 97 |
Page 98 |
Page 99 |
Page 100 |
Page 101 |
Page 102 |
Page 103 |
Page 104 |
Page 105 |
Page 106 |
Page 107 |
Page 108 |
Page 109 |
Page 110 |
Page 111 |
Page 112 |
Page 113 |
Page 114 |
Page 115 |
Page 116 |
Page 117 |
Page 118 |
Page 119 |
Page 120 |
Page 121 |
Page 122 |
Page 123 |
Page 124 |
Page 125 |
Page 126 |
Page 127 |
Page 128 |
Page 129 |
Page 130 |
Page 131 |
Page 132 |
Page 133 |
Page 134 |
Page 135 |
Page 136 |
Page 137 |
Page 138 |
Page 139 |
Page 140 |
Page 141 |
Page 142 |
Page 143 |
Page 144 |
Page 145 |
Page 146 |
Page 147 |
Page 148 |
Page 149 |
Page 150 |
Page 151 |
Page 152 |
Page 153 |
Page 154 |
Page 155 |
Page 156 |
Page 157 |
Page 158 |
Page 159 |
Page 160 |
Page 161 |
Page 162 |
Page 163 |
Page 164 |
Page 165 |
Page 166