Transition Year Maths Example 2:
The manufacturers of a small rocket claim its motion is given by x = 3t 2
+ 2t. Therefore the distance x it will
move in metres can be found by putting the time t into the formula. After three seconds it will move 3(3)2
+ 2(3) = 33 metres.
Using calculus we can find its velocity or acceleration at any time t.
Motion is defined by Velocity is defined by
Acceleration is defined by x = 3t 2
v dx dt
a dv dt
(x) (v) + 2t == t + ==6
Time Distance Velocity Acceleration (t)
t 3t 2 + 2t
0 sec 0 m 1 sec 5 m 2 sec 16 m 3 sec 33 m
6t + 2 2 m/s 8 m/s
14 m/s 20 m/s
(a) 6
6 m/s2 6 m/s2 6 m/s2 6 m/s2
Examine this to see if it is true! • If a car moves 16 m in 2 seconds, its average velocity should be 8 m per sec, and it is 8 m/s after 1 sec, half way between 0 sec and 2 sec.
• If a car moves from 5 m to 33 m in the 2 sec from 1 sec to 3 sec, the average velocity should be
33 ==5 2
–
28 2
14 m/s, and it is after 2 sec.
• If velocity increases from 8 m/s after 1 sec to 14 m/s after 2 sec it is accelerating at 6 m/s per sec ⇒acceleration = 6 m/s2
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