Q7 A sphere of mass 4 kg travelling at 4 m s1 hits a sphere of mass 2 kg travelling at 3 m s1 in the opposite direction. After the collision the heavier sphere travels at 1 m s1 in its original direction. What is the speed of the second sphere?
Q8 A pheasant, with a mass of 2 kg, is flying due east at 6.1 m s1 (minding its own business) when shot by a 35 g bullet travelling 350 m s1 due north.What is the speed of the pheasant immediately after impact? You may assume the bullet lodges in the pheasant.
MANDATORY EXPERIMENT 3
Verification of the Principle of Conservation of Momentum
Ticker timer
Ticker tape
Trolley 1 Magnet Runway Magnet Trolley 2
Fig 3.1
Apparatus Ticker tape, ticker timer, two trolleys, sloped runway, metre stick, magnets, electronic balance
Procedure Find the mass of both trolleys using an electronic balance. Set up apparatus as illustrated in Fig 3.1.Attach one end of ticker tape to trolley 1 and place other end through ticker timer. Place trolley 2 at rest on the runway.
Slope the runway so that the trolleys will move at constant velocity when given an initial push. Push trolley 1 and allow it to collide with and stick to trolley 2. Use the ticker timer to calculate the velocity of trolley 1 before collision (u), as described in Mandatory Experiment 1(A). Initial velocity of trolley 2 was zero before collision.
Use the ticker timer to calculate the velocity of the trolleys after the collision (v). Both trolleys have the same velocity after collision because they are stuck together.
Calculations Apply the formula m1u (m1 m2) v. This is equivalent to m1u1 m2u2 m1v1 m2v2.
