Therefore:


Displacement for 5.0357 m draught


TPC for 5.0357 m draught LCF for 5.0357 m draught


= 19743 +(20167-19743) x 3.57 = 10


= 42.32 +(42.37-42.32) x 3.57 = 10


19894.37 42.338


= - 4.354 +(4.354-4.289) x 3.57 = - 4.331 (for’d of mid) 10


MCTC for 5.0357 +50 cms = 445.5 +(446.6-445.5) x 3.57 = 10


MCTC for 5.0357 – 50 cms = 434.9 +(435.9-434.9) x 3.57 = 10


Therefore (dm~dz) = 10.63 The first trim correction is Second trim correction = =


101.73 x –4.331 x 42.338 = 181.8


1.01732 - 102.61tonnes


x 50 x 10.63 =+3.03 tonnes 181.8


Then vessels displacement at a density of 1.025 t/m3


Displacement for 5.0357m First trim correction Second trim correction


Corrected displacement in salt water


= = =


= is calculated as follows:


19894.37 tonnes -102.61 tonnes +3.03 tonnes


19794.79 tonnes


This is the weight of the ship at the draught if it was in salt water of density 1.025 t/m3 the ship’s hydrostatic scale.


However it is floating in water of apparent density 1.0185 t/m3 .


So true displacement = 19794.79 x 1.0185 = 19669.26 tonnes 1.025


, which is the density of 445.89 435.26


26


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